138 lines
3.8 KiB
SQL
138 lines
3.8 KiB
SQL
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--Axel, question 3 et 4
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--SELECT COUNT(id)
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--FROM SELECT idScientifique FROM Enseignant_Chercheur
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-- WHERE idScientifique = 01;
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--SELECT COUNT(idPublication) as nbCollab FROM Publication
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--WHERE classeConf = 'A';
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-- Nathan Q1
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SELECT Personnel.nom, Scientifique.grade FROM Personnel, Scientifique
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WHERE idPersonnel = idScientifique AND idPersonnel IN (
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SELECT idScientifique FROM Encadrement
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WHERE idDoctorant = 4
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);
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-- Ronan Q2
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SELECT ae.nom, ae.prenom le.pays FROM Personnel AS perso
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JOIN Publie_Scientifique ps on perso.idPersonnel = ps.idPersonnel
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RIGHT JOIN Publication publi on publi.idPublication = ps.idPublication
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RIGHT JOIN Publie_Externe pe on publi.idPublication = pe.idPublication
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JOIN Auteur_Externe ae on ae.idAuteur = pe.idAuteur
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JOIN Labo_Externe le on ae.idLabo = le.idLabo
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WHERE perso.nom = 'Azi'
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AND perso.prenom = 'Jean'
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AND annee >= '2016-01-01'
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AND annee <= '2020-01-01';
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--Axel Q3
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SELECT COUNT(DISTINCT idAuteurExterne) AS nbCollab FROM Publie_Externe pe
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JOIN Publie_Scientifique ps ON pe.idPublication = ps.idPublication
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RIGHT JOIN Publie_Doctorant pdoc ON pe.idPublication = pdoc.idPublication
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JOIN Enseignant_Chercheur ec ON ec.idEnseignant = ps.idScientifique
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WHERE idScientifique = '01';
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-- Axel Q4
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SELECT COUNT(DISTINCT ) as nbPaysCollab FROM Publication
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WHERE classeConf = 'A';
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-- Nathan Q5
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SELECT idDoctorant, COUNT(idPublication) FROM Publie_Doctorant
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GROUP BY idDoctorant;
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-- Ronan Q6
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SELECT COUNT(*) FROM Doctorant
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WHERE date_soutenance IS NOT NULL;
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--Nathan Q7
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SELECT nom, prenom FROM Personnel
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WHERE idPersonnel IN (
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SELECT idScientifique FROM Scientifique
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WHERE idScientifique NOT IN (
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SELECT idScientifique FROM Encadrement
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)
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);
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-- Nathan Q9
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SELECT nom, prenom FROM Personnel
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WHERE idPersonnel IN (
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SELECT idScientifique FROM Scientifique
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WHERE idScientifique IN (
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SELECT idScientifique FROM Encadrement
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WHERE idDoctorant IN (
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SELECT idDoctorant FROM Doctorant
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WHERE date_soutenance < NOW()
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)
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)
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);
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-- Ronan Q10
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SELECT idDoctorant, nom, prenom, COUNT(*) FROM Encadrement
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JOIN Scientifique on idPersonnel=idScientifique
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GROUP BY idDoctorant, nom, prenom
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HAVING COUNT(DISTINCT idScientifique)=1;
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-- Ronan Q16
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SELECT pays, COUNT(*) nb_publi
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FROM Labo_Externe
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JOIN Auteur_Externe ae on ae.idLabo = Labo_Externe.idLabo
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JOIN Publie_Externe pe on pe.idAuteur = ae.idAuteur
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GROUP BY pays
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ORDER BY nb_publi DESC LIMIT 1;
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--Yasmine QUESTION 5 A tester enc
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SELECT idDoctorant, count(distinct idPublication) as NombrePublication
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FROM Doctorant D
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LEFT JOIN Publie_Doctorant PD on PD.idDoctorant= D.idDoctorant
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GROUP BY idDoctorant;
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--Yasmine QUESTION 8
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SELECT idEnseignant
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FROM Enseignant_chercheur
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NOT IN ( (SELECT idScientifique
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FROM Publie_scientifique)
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UNION
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(SELECT idScientifique
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FROM Encadrement)
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) ;
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-- Yasmine QUESTION 14 Testé
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SELECT Count(Distinct idPublication)
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FROM Publication
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GROUP BY publication.annee;
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-- Yasmine QUESTION 15 Testé PAS D'ERREUR DE SYNTAXE
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SELECT Count(Distinct E.idEnseignant)
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FROM Enseignant_chercheur E,Personnel P ,Scientifique S
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WHERE P.idPersonnel=S.idScientifique
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AND S.idScientifique=E.idEnseignant
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GROUP BY idEtablissement;
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-- Yasmine QUESTION 19 Testé PAS D'ERREUR DE SYNTAXE
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SELECT idEtablissement, Count(Distinct idEnseignant)
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FROM Enseignant_chercheur
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GROUP BY idEtablissement
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HAVING count(Distinct idEnseignant) >= 50;
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--Yasmine QUESTION 21 Testé PAS D'ERREUR DE SYNTAXE
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SELECT Distinct P.Pays
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FROM Partenaire P, Participe_externe PEX
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where P.idpartenaire=PEX.idpartenaire
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and not exists (Select *
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From Projet PR
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Where not exists (Select *
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From Participe_externe PEX2
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Where PEX2.idPartenaire=P.idPartenaire and
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PEX2.idProjet=PR.idProjet));
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